Showing posts with label documents. Show all posts
Showing posts with label documents. Show all posts

Tuesday, March 20, 2012

Creating subreport from another subreport

Hi! I hope someone could help me...

I created three report documents, the main report, a subreport of the main report, and a subreport of the subreport. The problem is I can no longer create a subreport under a subreport, but each subreport is dependent to one another. Can anyone please give me an idea or other options to do this?

Thanks!With my knowledge you cannot create a subreport in a sub report. All the subreports are either should link to main report or can be placed independently to the main report with out linking to the main report. If you elaboreate your question more possibly i may answer your question.

Saturday, February 25, 2012

creating N xml documents from N rows

kudos to anyone who can answer this one;

I've got a table and I want to select rows in it so that the result contains an XML column. So going from

ID Parent Name Date

1 null Foo 2005-04-03

2 1 Bar 2005-04-03

to

ID Parent XML

1 null <element name="Foo" date="2005-04-03" />

2 1 <element name="Bar" date="2005-04-03" />

And for the life of me I can't find a method for creating the XML in an elegant way.

The 'FOR XML EXPLICIT' clause gives me all the formatting I could want, but forces you to munge all the XML into a single, xml-only result. That doesn't seem to be a help. Is there a clean way to do this?

If all else fails, though I shudder even to suggest it, is there a function to xml-escape strings so I can do something like

select

ID, Parent,

convert(xml, '<element name="' + quote(name) + '" date="' + quote(tostring(date)) + '" />")

from Elements

If you SQL Server 2005 you can use the following query,

Code Snippet

Create Table #data (

[ID] int ,

[Parent] Varchar(100) ,

[Name] Varchar(100) ,

[Date] datetime

);

Insert Into #data Values('1',NULL,'Foo','2005-04-03');

Insert Into #data Values('2','1','Bar','2005-04-03');

Select

Id

,Parent

,(Select [Name],[Date] from #Data element Where element.Id=Main.ID For XML AUTO) as XML

From

#Data Main

|||Wow -- thanks. That's absolutely perfect. Thanks so much.|||

this one also will work:

select
ID,
Parent,
(
select
quote(name) as "@.name",
quote(tostring(date)) as "@.daae"
for xml path('element'), type
) xml
from Elements